Solve 11/2-(-1/6)-7/3

$$\frac { 11 } { 2 } - ( - \frac { 1 } { 6 } ) - \frac { 7 } { 3 }$$

Evaluate

$$\frac{10}{3}\approx 3.333333333$$

Solution Steps

The opposite of -\frac{1}{6} is \frac{1}{6}.

$$\frac{11}{2}+\frac{1}{6}-\frac{7}{3}$$

Least common multiple of 2 and 6 is 6. Convert \frac{11}{2} and \frac{1}{6} to fractions with denominator 6.

$$\frac{33}{6}+\frac{1}{6}-\frac{7}{3}$$

Since \frac{33}{6} and \frac{1}{6} have the same denominator, add them by adding their numerators.

$$\frac{33+1}{6}-\frac{7}{3}$$

Add 33 and 1 to get 34.

$$\frac{34}{6}-\frac{7}{3}$$

Reduce the fraction \frac{34}{6} to lowest terms by extracting and canceling out 2.

$$\frac{17}{3}-\frac{7}{3}$$

Since \frac{17}{3} and \frac{7}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{17-7}{3}$$

Subtract 7 from 17 to get 10.

$$\frac{10}{3}$$

Factor

$$\frac{2 \cdot 5}{3} = 3\frac{1}{3} = 3.3333333333333335$$