Solve 101/18+b/12

$$\frac { 101 } { 18 } + \frac { b } { 12 }$$

Evaluate

$$\frac{b}{12}+\frac{101}{18}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 18 and 12 is 36. Multiply \frac{101}{18} times \frac{2}{2}. Multiply \frac{b}{12} times \frac{3}{3}.

$$\frac{101\times 2}{36}+\frac{3b}{36}$$

Since \frac{101\times 2}{36} and \frac{3b}{36} have the same denominator, add them by adding their numerators.

$$\frac{101\times 2+3b}{36}$$

Do the multiplications in 101\times 2+3b.

$$\frac{202+3b}{36}$$

Factor

$$\frac{3b+202}{36}$$

Solution Steps

Factor out \frac{1}{36}.

$$\frac{202+3b}{36}$$