Solve 10/a^2-a-6+1/a-3

$$\frac { 10 } { a ^ { 2 } - a - 6 } + \frac { 1 } { a - 3 }$$

Evaluate

$$\frac{a+12}{\left(a-3\right)\left(a+2\right)}$$

Short Solution Steps

Factor a^{2}-a-6.

$$\frac{10}{\left(a-3\right)\left(a+2\right)}+\frac{1}{a-3}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of \left(a-3\right)\left(a+2\right) and a-3 is \left(a-3\right)\left(a+2\right). Multiply \frac{1}{a-3} times \frac{a+2}{a+2}.

$$\frac{10}{\left(a-3\right)\left(a+2\right)}+\frac{a+2}{\left(a-3\right)\left(a+2\right)}$$

Since \frac{10}{\left(a-3\right)\left(a+2\right)} and \frac{a+2}{\left(a-3\right)\left(a+2\right)} have the same denominator, add them by adding their numerators.

$$\frac{10+a+2}{\left(a-3\right)\left(a+2\right)}$$

Combine like terms in 10+a+2.

$$\frac{12+a}{\left(a-3\right)\left(a+2\right)}$$

Expand \left(a-3\right)\left(a+2\right).

$$\frac{12+a}{a^{2}-a-6}$$

Differentiate w.r.t. a

$$\frac{6-24a-a^{2}}{a^{4}-2a^{3}-11a^{2}+12a+36}$$

Steps Using Derivative Rule for Quotient

Factor a^{2}-a-6.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{10}{\left(a-3\right)\left(a+2\right)}+\frac{1}{a-3})$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of \left(a-3\right)\left(a+2\right) and a-3 is \left(a-3\right)\left(a+2\right). Multiply \frac{1}{a-3} times \frac{a+2}{a+2}.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{10}{\left(a-3\right)\left(a+2\right)}+\frac{a+2}{\left(a-3\right)\left(a+2\right)})$$

Since \frac{10}{\left(a-3\right)\left(a+2\right)} and \frac{a+2}{\left(a-3\right)\left(a+2\right)} have the same denominator, add them by adding their numerators.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{10+a+2}{\left(a-3\right)\left(a+2\right)})$$

Combine like terms in 10+a+2.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{12+a}{\left(a-3\right)\left(a+2\right)})$$

Use the distributive property to multiply a-3 by a+2 and combine like terms.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{12+a}{a^{2}-a-6})$$

For any two differentiable functions, the derivative of the quotient of two functions is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the denominator squared.

$$\frac{\left(a^{2}-a^{1}-6\right)\frac{\mathrm{d}}{\mathrm{d}a}(a^{1}+12)-\left(a^{1}+12\right)\frac{\mathrm{d}}{\mathrm{d}a}(a^{2}-a^{1}-6)}{\left(a^{2}-a^{1}-6\right)^{2}}$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$\frac{\left(a^{2}-a^{1}-6\right)a^{1-1}-\left(a^{1}+12\right)\left(2a^{2-1}-a^{1-1}\right)}{\left(a^{2}-a^{1}-6\right)^{2}}$$

Simplify.

$$\frac{\left(a^{2}-a^{1}-6\right)a^{0}-\left(a^{1}+12\right)\left(2a^{1}-a^{0}\right)}{\left(a^{2}-a^{1}-6\right)^{2}}$$

Multiply a^{2}-a^{1}-6 times a^{0}.

$$\frac{a^{2}a^{0}-a^{1}a^{0}-6a^{0}-\left(a^{1}+12\right)\left(2a^{1}-a^{0}\right)}{\left(a^{2}-a^{1}-6\right)^{2}}$$

Multiply a^{1}+12 times 2a^{1}-a^{0}.

$$\frac{a^{2}a^{0}-a^{1}a^{0}-6a^{0}-\left(a^{1}\times 2a^{1}+a^{1}\left(-1\right)a^{0}+12\times 2a^{1}+12\left(-1\right)a^{0}\right)}{\left(a^{2}-a^{1}-6\right)^{2}}$$

To multiply powers of the same base, add their exponents.

$$\frac{a^{2}-a^{1}-6a^{0}-\left(2a^{1+1}-a^{1}+12\times 2a^{1}+12\left(-1\right)a^{0}\right)}{\left(a^{2}-a^{1}-6\right)^{2}}$$

Simplify.

$$\frac{a^{2}-a^{1}-6a^{0}-\left(2a^{2}-a^{1}+24a^{1}-12a^{0}\right)}{\left(a^{2}-a^{1}-6\right)^{2}}$$

Combine like terms.

$$\frac{-a^{2}-24a^{1}+6a^{0}}{\left(a^{2}-a^{1}-6\right)^{2}}$$

For any term t, t^{1}=t.

$$\frac{-a^{2}-24a+6a^{0}}{\left(a^{2}-a-6\right)^{2}}$$

For any term t except 0, t^{0}=1.

$$\frac{-a^{2}-24a+6\times 1}{\left(a^{2}-a-6\right)^{2}}$$

For any term t, t\times 1=t and 1t=t.

$$\frac{-a^{2}-24a+6}{\left(a^{2}-a-6\right)^{2}}$$