Solve 10+x^3/c+10=185

$$\frac { 10 + x ^ { 3 } } { c + 10 } = 185$$

Solve for c

$$c=\frac{x^{3}-1840}{185}$$

$$x\neq -\sqrt[3]{10}$$

Steps for Solving Linear Equation

Variable c cannot be equal to -10 since division by zero is not defined. Multiply both sides of the equation by c+10.

$$10+x^{3}=185\left(c+10\right)$$

Use the distributive property to multiply 185 by c+10.

$$10+x^{3}=185c+1850$$

Swap sides so that all variable terms are on the left hand side.

$$185c+1850=10+x^{3}$$

Subtract 1850 from both sides.

$$185c=10+x^{3}-1850$$

Subtract 1850 from 10 to get -1840.

$$185c=-1840+x^{3}$$

The equation is in standard form.

$$185c=x^{3}-1840$$

Divide both sides by 185.

$$\frac{185c}{185}=\frac{x^{3}-1840}{185}$$

Dividing by 185 undoes the multiplication by 185.

$$c=\frac{x^{3}-1840}{185}$$

Divide -1840+x^{3} by 185.

$$c=\frac{x^{3}}{185}-\frac{368}{37}$$

Variable c cannot be equal to -10.

$$c=\frac{x^{3}}{185}-\frac{368}{37}\text{, }c\neq -10$$

Solve for x

$$x=\sqrt[3]{185c+1840}$$

$$c\neq -10$$