Solve 1/y-5/2y-3/y^2

$$\frac { 1 } { y } - \frac { 5 } { 2 y } - \frac { 3 } { y ^ { 2 } }$$

Evaluate

$$-\frac{3\left(y+2\right)}{2y^{2}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of y and 2y is 2y. Multiply \frac{1}{y} times \frac{2}{2}.

$$\frac{2}{2y}-\frac{5}{2y}-\frac{3}{y^{2}}$$

Since \frac{2}{2y} and \frac{5}{2y} have the same denominator, subtract them by subtracting their numerators. Subtract 5 from 2 to get -3.

$$\frac{-3}{2y}-\frac{3}{y^{2}}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 2y and y^{2} is 2y^{2}. Multiply \frac{-3}{2y} times \frac{y}{y}. Multiply \frac{3}{y^{2}} times \frac{2}{2}.

$$\frac{-3y}{2y^{2}}-\frac{3\times 2}{2y^{2}}$$

Since \frac{-3y}{2y^{2}} and \frac{3\times 2}{2y^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-3y-3\times 2}{2y^{2}}$$

Do the multiplications in -3y-3\times 2.

$$\frac{-3y-6}{2y^{2}}$$

Factor

$$-\frac{3\left(y+2\right)}{2y^{2}}$$