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2+2y\left(-\frac{1}{2}\right)+2y=0
Consider the second equation. Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 2y, the least common multiple of y,2.
2-y+2y=0
Multiply 2 and -\frac{1}{2} to get -1.
2+y=0
Combine -y and 2y to get y.
y=-2
Subtract 2 from both sides. Anything subtracted from zero gives its negation.
\frac{1}{x}-\frac{2}{-2}+4=0
Consider the first equation. Insert the known values of variables into the equation.
2-\left(-x\times 2\right)+2x\times 4=0
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 2x, the least common multiple of x,-2.
2-\left(-2x\right)+2x\times 4=0
Multiply -1 and 2 to get -2.
2+2x+2x\times 4=0
The opposite of -2x is 2x.
2+2x+8x=0
Multiply 2 and 4 to get 8.
2+10x=0
Combine 2x and 8x to get 10x.
10x=-2
Subtract 2 from both sides. Anything subtracted from zero gives its negation.
x=\frac{-2}{10}
Divide both sides by 10.
x=-\frac{1}{5}
Reduce the fraction \frac{-2}{10} to lowest terms by extracting and canceling out 2.
\frac{2}{z}+\frac{3}{-\frac{1}{5}}=14
Consider the third equation. Insert the known values of variables into the equation.
2+z\times \frac{3}{-\frac{1}{5}}=14z
Variable z cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by z.
2+z\times 3\left(-5\right)=14z
Divide 3 by -\frac{1}{5} by multiplying 3 by the reciprocal of -\frac{1}{5}.
2+z\left(-15\right)=14z
Multiply 3 and -5 to get -15.
2+z\left(-15\right)-14z=0
Subtract 14z from both sides.
2-29z=0
Combine z\left(-15\right) and -14z to get -29z.
-29z=-2
Subtract 2 from both sides. Anything subtracted from zero gives its negation.
z=\frac{-2}{-29}
Divide both sides by -29.
z=\frac{2}{29}
Fraction \frac{-2}{-29} can be simplified to \frac{2}{29} by removing the negative sign from both the numerator and the denominator.
x=-\frac{1}{5} y=-2 z=\frac{2}{29}
The system is now solved.