Solve 1/f(2)=2^2+2-2

$$\frac { 1 } { f ( 2 ) } = 2 ^ { 2 } + 2 - 2$$

Solve for f

$$f=\frac{1}{8}=0.125$$

Steps for Solving Linear Equation

Variable f cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 2f.

$$1=2f\times 2^{2}+2f\times 2+2f\left(-2\right)$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$1=2^{3}f+2f\times 2+2f\left(-2\right)$$

Calculate 2 to the power of 3 and get 8.

$$1=8f+2f\times 2+2f\left(-2\right)$$

Multiply 2 and 2 to get 4.

$$1=8f+4f+2f\left(-2\right)$$

Combine 8f and 4f to get 12f.

$$1=12f+2f\left(-2\right)$$

Multiply 2 and -2 to get -4.

$$1=12f-4f$$

Combine 12f and -4f to get 8f.

$$1=8f$$

Swap sides so that all variable terms are on the left hand side.

$$8f=1$$

Divide both sides by 8.

$$f=\frac{1}{8}$$