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\frac{16x^{2}y^{2}-9y^{2}z^{2}}{144}
Factor out \frac{1}{144}.
y^{2}\left(16x^{2}-9z^{2}\right)
Consider 16x^{2}y^{2}-9y^{2}z^{2}. Factor out y^{2}.
\left(4x-3z\right)\left(4x+3z\right)
Consider 16x^{2}-9z^{2}. Rewrite 16x^{2}-9z^{2} as \left(4x\right)^{2}-\left(3z\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{y^{2}\left(4x-3z\right)\left(4x+3z\right)}{144}
Rewrite the complete factored expression.