Solve 1/9+2/6+3/4=

$$\frac { 1 } { 9 } + \frac { 2 } { 6 } + \frac { 3 } { 4 } =$$

Evaluate

$$\frac{43}{36}\approx 1.194444444$$

Solution Steps

Reduce the fraction \frac{2}{6} to lowest terms by extracting and canceling out 2.

$$\frac{1}{9}+\frac{1}{3}+\frac{3}{4}$$

Least common multiple of 9 and 3 is 9. Convert \frac{1}{9} and \frac{1}{3} to fractions with denominator 9.

$$\frac{1}{9}+\frac{3}{9}+\frac{3}{4}$$

Since \frac{1}{9} and \frac{3}{9} have the same denominator, add them by adding their numerators.

$$\frac{1+3}{9}+\frac{3}{4}$$

Add 1 and 3 to get 4.

$$\frac{4}{9}+\frac{3}{4}$$

Least common multiple of 9 and 4 is 36. Convert \frac{4}{9} and \frac{3}{4} to fractions with denominator 36.

$$\frac{16}{36}+\frac{27}{36}$$

Since \frac{16}{36} and \frac{27}{36} have the same denominator, add them by adding their numerators.

$$\frac{16+27}{36}$$

Add 16 and 27 to get 43.

$$\frac{43}{36}$$

Factor

$$\frac{43}{2 ^ {2} \cdot 3 ^ {2}} = 1\frac{7}{36} = 1.1944444444444444$$