Solve 1/9+1/8-(-64)+1

$$\frac { 1 } { 9 } + \frac { 1 } { 8 } - ( - 64 ) + 1$$

Evaluate

$$\frac{4697}{72}\approx 65.236111111$$

Solution Steps

Least common multiple of 9 and 8 is 72. Convert \frac{1}{9} and \frac{1}{8} to fractions with denominator 72.

$$\frac{8}{72}+\frac{9}{72}-\left(-64\right)+1$$

Since \frac{8}{72} and \frac{9}{72} have the same denominator, add them by adding their numerators.

$$\frac{8+9}{72}-\left(-64\right)+1$$

Add 8 and 9 to get 17.

$$\frac{17}{72}-\left(-64\right)+1$$

The opposite of -64 is 64.

$$\frac{17}{72}+64+1$$

Convert 64 to fraction \frac{4608}{72}.

$$\frac{17}{72}+\frac{4608}{72}+1$$

Since \frac{17}{72} and \frac{4608}{72} have the same denominator, add them by adding their numerators.

$$\frac{17+4608}{72}+1$$

Add 17 and 4608 to get 4625.

$$\frac{4625}{72}+1$$

Convert 1 to fraction \frac{72}{72}.

$$\frac{4625}{72}+\frac{72}{72}$$

Since \frac{4625}{72} and \frac{72}{72} have the same denominator, add them by adding their numerators.

$$\frac{4625+72}{72}$$

Add 4625 and 72 to get 4697.

$$\frac{4697}{72}$$

Factor

$$\frac{7 \cdot 11 \cdot 61}{2 ^ {3} \cdot 3 ^ {2}} = 65\frac{17}{72} = 65.23611111111111$$