Solve for x
x=11
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\frac{1}{7}\times 3x+\frac{1}{7}\times 2-\frac{1}{5}\left(x+4\right)=2
Use the distributive property to multiply \frac{1}{7} by 3x+2.
\frac{3}{7}x+\frac{1}{7}\times 2-\frac{1}{5}\left(x+4\right)=2
Multiply \frac{1}{7} and 3 to get \frac{3}{7}.
\frac{3}{7}x+\frac{2}{7}-\frac{1}{5}\left(x+4\right)=2
Multiply \frac{1}{7} and 2 to get \frac{2}{7}.
\frac{3}{7}x+\frac{2}{7}-\frac{1}{5}x-\frac{1}{5}\times 4=2
Use the distributive property to multiply -\frac{1}{5} by x+4.
\frac{3}{7}x+\frac{2}{7}-\frac{1}{5}x+\frac{-4}{5}=2
Express -\frac{1}{5}\times 4 as a single fraction.
\frac{3}{7}x+\frac{2}{7}-\frac{1}{5}x-\frac{4}{5}=2
Fraction \frac{-4}{5} can be rewritten as -\frac{4}{5} by extracting the negative sign.
\frac{8}{35}x+\frac{2}{7}-\frac{4}{5}=2
Combine \frac{3}{7}x and -\frac{1}{5}x to get \frac{8}{35}x.
\frac{8}{35}x+\frac{10}{35}-\frac{28}{35}=2
Least common multiple of 7 and 5 is 35. Convert \frac{2}{7} and \frac{4}{5} to fractions with denominator 35.
\frac{8}{35}x+\frac{10-28}{35}=2
Since \frac{10}{35} and \frac{28}{35} have the same denominator, subtract them by subtracting their numerators.
\frac{8}{35}x-\frac{18}{35}=2
Subtract 28 from 10 to get -18.
\frac{8}{35}x=2+\frac{18}{35}
Add \frac{18}{35} to both sides.
\frac{8}{35}x=\frac{70}{35}+\frac{18}{35}
Convert 2 to fraction \frac{70}{35}.
\frac{8}{35}x=\frac{70+18}{35}
Since \frac{70}{35} and \frac{18}{35} have the same denominator, add them by adding their numerators.
\frac{8}{35}x=\frac{88}{35}
Add 70 and 18 to get 88.
x=\frac{88}{35}\times \frac{35}{8}
Multiply both sides by \frac{35}{8}, the reciprocal of \frac{8}{35}.
x=\frac{88\times 35}{35\times 8}
Multiply \frac{88}{35} times \frac{35}{8} by multiplying numerator times numerator and denominator times denominator.
x=\frac{88}{8}
Cancel out 35 in both numerator and denominator.
x=11
Divide 88 by 8 to get 11.
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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