Solve 1/6+4/12=1-3/6

$$\frac { 1 } { 6 } + \frac { 4 } { 12 } = 1 - \frac { 3 } { 6 }$$

Verify

Solution Steps

Reduce the fraction \frac{4}{12} to lowest terms by extracting and canceling out 4.

$$\frac{1}{6}+\frac{1}{3}=1-\frac{3}{6}$$

Least common multiple of 6 and 3 is 6. Convert \frac{1}{6} and \frac{1}{3} to fractions with denominator 6.

$$\frac{1}{6}+\frac{2}{6}=1-\frac{3}{6}$$

Since \frac{1}{6} and \frac{2}{6} have the same denominator, add them by adding their numerators.

$$\frac{1+2}{6}=1-\frac{3}{6}$$

Add 1 and 2 to get 3.

$$\frac{3}{6}=1-\frac{3}{6}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$\frac{1}{2}=1-\frac{3}{6}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$\frac{1}{2}=1-\frac{1}{2}$$

Convert 1 to fraction \frac{2}{2}.

$$\frac{1}{2}=\frac{2}{2}-\frac{1}{2}$$

Since \frac{2}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{2}=\frac{2-1}{2}$$

Subtract 1 from 2 to get 1.

$$\frac{1}{2}=\frac{1}{2}$$

Compare \frac{1}{2} and \frac{1}{2}.

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