Solve 1/6+3/12+1/3=

$$\frac { 1 } { 6 } + \frac { 3 } { 12 } + \frac { 1 } { 3 } =$$

Evaluate

$$\frac{3}{4}=0.75$$

Solution Steps

Reduce the fraction \frac{3}{12} to lowest terms by extracting and canceling out 3.

$$\frac{1}{6}+\frac{1}{4}+\frac{1}{3}$$

Least common multiple of 6 and 4 is 12. Convert \frac{1}{6} and \frac{1}{4} to fractions with denominator 12.

$$\frac{2}{12}+\frac{3}{12}+\frac{1}{3}$$

Since \frac{2}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.

$$\frac{2+3}{12}+\frac{1}{3}$$

Add 2 and 3 to get 5.

$$\frac{5}{12}+\frac{1}{3}$$

Least common multiple of 12 and 3 is 12. Convert \frac{5}{12} and \frac{1}{3} to fractions with denominator 12.

$$\frac{5}{12}+\frac{4}{12}$$

Since \frac{5}{12} and \frac{4}{12} have the same denominator, add them by adding their numerators.

$$\frac{5+4}{12}$$

Add 5 and 4 to get 9.

$$\frac{9}{12}$$

Reduce the fraction \frac{9}{12} to lowest terms by extracting and canceling out 3.

$$\frac{3}{4}$$

Factor

$$\frac{3}{2 ^ {2}} = 0.75$$