Solve 1/5+1/10+1/430

$$\frac { 1 } { 5 } + \frac { 1 } { 10 } + \frac { 1 } { 430 }$$

Evaluate

$$\frac{13}{43}\approx 0.302325581$$

Solution Steps

Least common multiple of 5 and 10 is 10. Convert \frac{1}{5} and \frac{1}{10} to fractions with denominator 10.

$$\frac{2}{10}+\frac{1}{10}+\frac{1}{430}$$

Since \frac{2}{10} and \frac{1}{10} have the same denominator, add them by adding their numerators.

$$\frac{2+1}{10}+\frac{1}{430}$$

Add 2 and 1 to get 3.

$$\frac{3}{10}+\frac{1}{430}$$

Least common multiple of 10 and 430 is 430. Convert \frac{3}{10} and \frac{1}{430} to fractions with denominator 430.

$$\frac{129}{430}+\frac{1}{430}$$

Since \frac{129}{430} and \frac{1}{430} have the same denominator, add them by adding their numerators.

$$\frac{129+1}{430}$$

Add 129 and 1 to get 130.

$$\frac{130}{430}$$

Reduce the fraction \frac{130}{430} to lowest terms by extracting and canceling out 10.

$$\frac{13}{43}$$

Factor

$$\frac{13}{43} = 0.3023255813953488$$