Solve 1/40+18/4leq2

$$\frac { 1 } { 40 } + \frac { 18 } { 4 } \leq 2$$

Verify

Solution Steps

Reduce the fraction \frac{18}{4} to lowest terms by extracting and canceling out 2.

$$\frac{1}{40}+\frac{9}{2}\leq 2$$

Least common multiple of 40 and 2 is 40. Convert \frac{1}{40} and \frac{9}{2} to fractions with denominator 40.

$$\frac{1}{40}+\frac{180}{40}\leq 2$$

Since \frac{1}{40} and \frac{180}{40} have the same denominator, add them by adding their numerators.

$$\frac{1+180}{40}\leq 2$$

Add 1 and 180 to get 181.

$$\frac{181}{40}\leq 2$$

Convert 2 to fraction \frac{80}{40}.

$$\frac{181}{40}\leq \frac{80}{40}$$

Compare \frac{181}{40} and \frac{80}{40}.

$$\text{false}$$