Solve 1/4s-3leq1/8(3+25)

$$\frac { 1 } { 4 } s - 3 \leq \frac { 1 } { 8 } ( 3 + 25 )$$

Solve for s

$$s\leq 26$$

Solution Steps

Add 3 and 25 to get 28.

$$\frac{1}{4}s-3\leq \frac{1}{8}\times 28$$

Multiply \frac{1}{8} and 28 to get \frac{28}{8}.

$$\frac{1}{4}s-3\leq \frac{28}{8}$$

Reduce the fraction \frac{28}{8} to lowest terms by extracting and canceling out 4.

$$\frac{1}{4}s-3\leq \frac{7}{2}$$

Add 3 to both sides.

$$\frac{1}{4}s\leq \frac{7}{2}+3$$

Convert 3 to fraction \frac{6}{2}.

$$\frac{1}{4}s\leq \frac{7}{2}+\frac{6}{2}$$

Since \frac{7}{2} and \frac{6}{2} have the same denominator, add them by adding their numerators.

$$\frac{1}{4}s\leq \frac{7+6}{2}$$

Add 7 and 6 to get 13.

$$\frac{1}{4}s\leq \frac{13}{2}$$

Multiply both sides by 4, the reciprocal of \frac{1}{4}. Since \frac{1}{4} is positive, the inequality direction remains the same.

$$s\leq \frac{13}{2}\times 4$$

Express \frac{13}{2}\times 4 as a single fraction.

$$s\leq \frac{13\times 4}{2}$$

Multiply 13 and 4 to get 52.

$$s\leq \frac{52}{2}$$

Divide 52 by 2 to get 26.

$$s\leq 26$$