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\frac{1-64z^{2}}{4}
Factor out \frac{1}{4}.
\left(1-8z\right)\left(1+8z\right)
Consider 1-64z^{2}. Rewrite 1-64z^{2} as 1^{2}-\left(8z\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(-8z+1\right)\left(8z+1\right)
Reorder the terms.
\frac{\left(-8z+1\right)\left(8z+1\right)}{4}
Rewrite the complete factored expression.