Solve 1/4*(3-3b/2)+b/3=1/2

$$\frac { 1 } { 4 } \times ( 3 - \frac { 3 b } { 2 } ) + \frac { b } { 3 } = \frac { 1 } { 2 }$$

Solve for b

$$b=6$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 12, the least common multiple of 4,2,3.

$$3\left(3-\frac{3b}{2}\right)+4b=6$$

Use the distributive property to multiply 3 by 3-\frac{3b}{2}.

$$9+3\left(-\frac{3b}{2}\right)+4b=6$$

Express 3\left(-\frac{3b}{2}\right) as a single fraction.

$$9+\frac{-3\times 3b}{2}+4b=6$$

Multiply -3 and 3 to get -9.

$$9+\frac{-9b}{2}+4b=6$$

Subtract 9 from both sides.

$$\frac{-9b}{2}+4b=6-9$$

Subtract 9 from 6 to get -3.

$$\frac{-9b}{2}+4b=-3$$

Multiply both sides of the equation by 2.

$$-9b+8b=-6$$

Combine -9b and 8b to get -b.

$$-b=-6$$

Multiply both sides by -1.

$$b=6$$