Solve for x
x=-9
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\frac{1}{4}-\frac{8}{4}=\frac{1}{2}+\frac{1}{4}x
Convert 2 to fraction \frac{8}{4}.
\frac{1-8}{4}=\frac{1}{2}+\frac{1}{4}x
Since \frac{1}{4} and \frac{8}{4} have the same denominator, subtract them by subtracting their numerators.
-\frac{7}{4}=\frac{1}{2}+\frac{1}{4}x
Subtract 8 from 1 to get -7.
\frac{1}{2}+\frac{1}{4}x=-\frac{7}{4}
Swap sides so that all variable terms are on the left hand side.
\frac{1}{4}x=-\frac{7}{4}-\frac{1}{2}
Subtract \frac{1}{2} from both sides.
\frac{1}{4}x=-\frac{7}{4}-\frac{2}{4}
Least common multiple of 4 and 2 is 4. Convert -\frac{7}{4} and \frac{1}{2} to fractions with denominator 4.
\frac{1}{4}x=\frac{-7-2}{4}
Since -\frac{7}{4} and \frac{2}{4} have the same denominator, subtract them by subtracting their numerators.
\frac{1}{4}x=-\frac{9}{4}
Subtract 2 from -7 to get -9.
x=-\frac{9}{4}\times 4
Multiply both sides by 4, the reciprocal of \frac{1}{4}.
x=-9
Cancel out 4 and 4.
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y = 3x + 4
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Simultaneous equation
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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