Solve 1/3(8)+1/8=4/31

$$\frac { 1 } { 3 ( 8 ) } + \frac { 1 } { 8 } = \frac { 4 } { 31 }$$

Verify

Solution Steps

Multiply 3 and 8 to get 24.

$$\frac{1}{24}+\frac{1}{8}=\frac{4}{31}$$

Least common multiple of 24 and 8 is 24. Convert \frac{1}{24} and \frac{1}{8} to fractions with denominator 24.

$$\frac{1}{24}+\frac{3}{24}=\frac{4}{31}$$

Since \frac{1}{24} and \frac{3}{24} have the same denominator, add them by adding their numerators.

$$\frac{1+3}{24}=\frac{4}{31}$$

Add 1 and 3 to get 4.

$$\frac{4}{24}=\frac{4}{31}$$

Reduce the fraction \frac{4}{24} to lowest terms by extracting and canceling out 4.

$$\frac{1}{6}=\frac{4}{31}$$

Least common multiple of 6 and 31 is 186. Convert \frac{1}{6} and \frac{4}{31} to fractions with denominator 186.

$$\frac{31}{186}=\frac{24}{186}$$

Compare \frac{31}{186} and \frac{24}{186}.

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