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\frac{9z^{2}-1}{27}
Factor out \frac{1}{27}.
\left(3z-1\right)\left(3z+1\right)
Consider 9z^{2}-1. Rewrite 9z^{2}-1 as \left(3z\right)^{2}-1^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{\left(3z-1\right)\left(3z+1\right)}{27}
Rewrite the complete factored expression.