Solve 1/3y=-3+2x

$$\frac { 1 } { 3 } y = - 3 + 2 x$$

Solve for x

$$x=\frac{y+9}{6}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-3+2x=\frac{1}{3}y$$

Add 3 to both sides.

$$2x=\frac{1}{3}y+3$$

The equation is in standard form.

$$2x=\frac{y}{3}+3$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{\frac{y}{3}+3}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{\frac{y}{3}+3}{2}$$

Divide \frac{y}{3}+3 by 2.

$$x=\frac{y}{6}+\frac{3}{2}$$

Solve for y

$$y=6x-9$$

Steps for Solving Linear Equation

The equation is in standard form.

$$\frac{1}{3}y=2x-3$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}y}{\frac{1}{3}}=\frac{2x-3}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$y=\frac{2x-3}{\frac{1}{3}}$$

Divide -3+2x by \frac{1}{3} by multiplying -3+2x by the reciprocal of \frac{1}{3}.

$$y=6x-9$$