Solve 1/3y+3=1/4

$$\frac { 1 } { 3 } y + 3 = \frac { 1 } { 4 }$$

Solve for y

$$y = -\frac{33}{4} = -8\frac{1}{4} = -8.25$$

Steps for Solving Linear Equation

Subtract 3 from both sides.

$$\frac{1}{3}y=\frac{1}{4}-3$$

Convert 3 to fraction \frac{12}{4}.

$$\frac{1}{3}y=\frac{1}{4}-\frac{12}{4}$$

Since \frac{1}{4} and \frac{12}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{3}y=\frac{1-12}{4}$$

Subtract 12 from 1 to get -11.

$$\frac{1}{3}y=-\frac{11}{4}$$

Multiply both sides by 3, the reciprocal of \frac{1}{3}.

$$y=-\frac{11}{4}\times 3$$

Express -\frac{11}{4}\times 3 as a single fraction.

$$y=\frac{-11\times 3}{4}$$

Multiply -11 and 3 to get -33.

$$y=\frac{-33}{4}$$

Fraction \frac{-33}{4} can be rewritten as -\frac{33}{4} by extracting the negative sign.

$$y=-\frac{33}{4}$$