Factor
\frac{\left(x-3\right)\left(x^{2}-3x+3\right)}{3}
Evaluate
\frac{\left(x-3\right)\left(x^{2}-3x+3\right)}{3}
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\frac{x^{3}-6x^{2}+12x-9}{3}
Factor out \frac{1}{3}.
\left(x-3\right)\left(x^{2}-3x+3\right)
Consider x^{3}-6x^{2}+12x-9. By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term -9 and q divides the leading coefficient 1. One such root is 3. Factor the polynomial by dividing it by x-3.
\frac{\left(x-3\right)\left(x^{2}-3x+3\right)}{3}
Rewrite the complete factored expression. Polynomial x^{2}-3x+3 is not factored since it does not have any rational roots.
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