Solve for a
a=\frac{x^{3}+12}{3x}
x\neq 0
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ax=\frac{1}{3}x^{3}+4
Swap sides so that all variable terms are on the left hand side.
xa=\frac{x^{3}}{3}+4
The equation is in standard form.
\frac{xa}{x}=\frac{\frac{x^{3}}{3}+4}{x}
Divide both sides by x.
a=\frac{\frac{x^{3}}{3}+4}{x}
Dividing by x undoes the multiplication by x.
a=\frac{x^{2}}{3}+\frac{4}{x}
Divide \frac{x^{3}}{3}+4 by x.
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