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\frac{1}{3}-\frac{\frac{1}{4}}{-\frac{3}{8}}
Calculate -\frac{1}{2} to the power of 2 and get \frac{1}{4}.
\frac{1}{3}-\frac{1}{4}\left(-\frac{8}{3}\right)
Divide \frac{1}{4} by -\frac{3}{8} by multiplying \frac{1}{4} by the reciprocal of -\frac{3}{8}.
\frac{1}{3}-\frac{1\left(-8\right)}{4\times 3}
Multiply \frac{1}{4} times -\frac{8}{3} by multiplying numerator times numerator and denominator times denominator.
\frac{1}{3}-\frac{-8}{12}
Do the multiplications in the fraction \frac{1\left(-8\right)}{4\times 3}.
\frac{1}{3}-\left(-\frac{2}{3}\right)
Reduce the fraction \frac{-8}{12} to lowest terms by extracting and canceling out 4.
\frac{1}{3}+\frac{2}{3}
The opposite of -\frac{2}{3} is \frac{2}{3}.
\frac{1+2}{3}
Since \frac{1}{3} and \frac{2}{3} have the same denominator, add them by adding their numerators.
\frac{3}{3}
Add 1 and 2 to get 3.
1
Divide 3 by 3 to get 1.