Solve 1/3(x-4)-4=0

$$\frac { 1 } { 3 } ( x - 4 ) - 4 = 0$$

Solve for x

$$x=16$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{1}{3} by x-4.

$$\frac{1}{3}x+\frac{1}{3}\left(-4\right)-4=0$$

Multiply \frac{1}{3} and -4 to get \frac{-4}{3}.

$$\frac{1}{3}x+\frac{-4}{3}-4=0$$

Fraction \frac{-4}{3} can be rewritten as -\frac{4}{3} by extracting the negative sign.

$$\frac{1}{3}x-\frac{4}{3}-4=0$$

Convert 4 to fraction \frac{12}{3}.

$$\frac{1}{3}x-\frac{4}{3}-\frac{12}{3}=0$$

Since -\frac{4}{3} and \frac{12}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{3}x+\frac{-4-12}{3}=0$$

Subtract 12 from -4 to get -16.

$$\frac{1}{3}x-\frac{16}{3}=0$$

Add \frac{16}{3} to both sides. Anything plus zero gives itself.

$$\frac{1}{3}x=\frac{16}{3}$$

Multiply both sides by 3, the reciprocal of \frac{1}{3}.

$$x=\frac{16}{3}\times 3$$

Cancel out 3 and 3.

$$x=16$$