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Solve for x (complex solution)
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\frac{1}{3}\times 9+\frac{1}{3}\left(-2\right)x-1=-\frac{2}{3}x+2
Use the distributive property to multiply \frac{1}{3} by 9-2x.
\frac{9}{3}+\frac{1}{3}\left(-2\right)x-1=-\frac{2}{3}x+2
Multiply \frac{1}{3} and 9 to get \frac{9}{3}.
3+\frac{1}{3}\left(-2\right)x-1=-\frac{2}{3}x+2
Divide 9 by 3 to get 3.
3+\frac{-2}{3}x-1=-\frac{2}{3}x+2
Multiply \frac{1}{3} and -2 to get \frac{-2}{3}.
3-\frac{2}{3}x-1=-\frac{2}{3}x+2
Fraction \frac{-2}{3} can be rewritten as -\frac{2}{3} by extracting the negative sign.
2-\frac{2}{3}x=-\frac{2}{3}x+2
Subtract 1 from 3 to get 2.
2-\frac{2}{3}x+\frac{2}{3}x=2
Add \frac{2}{3}x to both sides.
2=2
Combine -\frac{2}{3}x and \frac{2}{3}x to get 0.
\text{true}
Compare 2 and 2.
x\in \mathrm{C}
This is true for any x.
\frac{1}{3}\times 9+\frac{1}{3}\left(-2\right)x-1=-\frac{2}{3}x+2
Use the distributive property to multiply \frac{1}{3} by 9-2x.
\frac{9}{3}+\frac{1}{3}\left(-2\right)x-1=-\frac{2}{3}x+2
Multiply \frac{1}{3} and 9 to get \frac{9}{3}.
3+\frac{1}{3}\left(-2\right)x-1=-\frac{2}{3}x+2
Divide 9 by 3 to get 3.
3+\frac{-2}{3}x-1=-\frac{2}{3}x+2
Multiply \frac{1}{3} and -2 to get \frac{-2}{3}.
3-\frac{2}{3}x-1=-\frac{2}{3}x+2
Fraction \frac{-2}{3} can be rewritten as -\frac{2}{3} by extracting the negative sign.
2-\frac{2}{3}x=-\frac{2}{3}x+2
Subtract 1 from 3 to get 2.
2-\frac{2}{3}x+\frac{2}{3}x=2
Add \frac{2}{3}x to both sides.
2=2
Combine -\frac{2}{3}x and \frac{2}{3}x to get 0.
\text{true}
Compare 2 and 2.
x\in \mathrm{R}
This is true for any x.