Solve 1/3(21/4*3/4-15/16)+frac{1}{4}

$$\frac { 1 } { 3 } ( 2 \frac { 1 } { 4 } \cdot \frac { 3 } { 4 } - \frac { 15 } { 16 } ) + \frac { 1 } { 4 }$$

Evaluate

$$\frac{1}{2}=0.5$$

Solution Steps

Multiply 2 and 4 to get 8.

$$\frac{1}{3}\left(\frac{8+1}{4}\times \frac{3}{4}-\frac{15}{16}\right)+\frac{1}{4}$$

Add 8 and 1 to get 9.

$$\frac{1}{3}\left(\frac{9}{4}\times \frac{3}{4}-\frac{15}{16}\right)+\frac{1}{4}$$

Multiply \frac{9}{4} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1}{3}\left(\frac{9\times 3}{4\times 4}-\frac{15}{16}\right)+\frac{1}{4}$$

Do the multiplications in the fraction \frac{9\times 3}{4\times 4}.

$$\frac{1}{3}\left(\frac{27}{16}-\frac{15}{16}\right)+\frac{1}{4}$$

Since \frac{27}{16} and \frac{15}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{3}\times \frac{27-15}{16}+\frac{1}{4}$$

Subtract 15 from 27 to get 12.

$$\frac{1}{3}\times \frac{12}{16}+\frac{1}{4}$$

Reduce the fraction \frac{12}{16} to lowest terms by extracting and canceling out 4.

$$\frac{1}{3}\times \frac{3}{4}+\frac{1}{4}$$

Multiply \frac{1}{3} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 3}{3\times 4}+\frac{1}{4}$$

Cancel out 3 in both numerator and denominator.

$$\frac{1}{4}+\frac{1}{4}$$

Since \frac{1}{4} and \frac{1}{4} have the same denominator, add them by adding their numerators.

$$\frac{1+1}{4}$$

Add 1 and 1 to get 2.

$$\frac{2}{4}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{1}{2}$$

Factor

$$\frac{1}{2} = 0.5$$