Solve frac{1}3^2+2*4/3-2/3+(-2/3)

$$\frac { 1 } { 3 } ^ { 2 } + 2 \times \frac { 4 } { 3 } - \frac { 2 } { 3 } + ( - \frac { 2 } { 3 } )$$

Evaluate

$$\frac{13}{9}\approx 1.444444444$$

Solution Steps

Calculate \frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$\frac{1}{9}+2\times \frac{4}{3}-\frac{2}{3}-\frac{2}{3}$$

Express 2\times \frac{4}{3} as a single fraction.

$$\frac{1}{9}+\frac{2\times 4}{3}-\frac{2}{3}-\frac{2}{3}$$

Multiply 2 and 4 to get 8.

$$\frac{1}{9}+\frac{8}{3}-\frac{2}{3}-\frac{2}{3}$$

Least common multiple of 9 and 3 is 9. Convert \frac{1}{9} and \frac{8}{3} to fractions with denominator 9.

$$\frac{1}{9}+\frac{24}{9}-\frac{2}{3}-\frac{2}{3}$$

Since \frac{1}{9} and \frac{24}{9} have the same denominator, add them by adding their numerators.

$$\frac{1+24}{9}-\frac{2}{3}-\frac{2}{3}$$

Add 1 and 24 to get 25.

$$\frac{25}{9}-\frac{2}{3}-\frac{2}{3}$$

Least common multiple of 9 and 3 is 9. Convert \frac{25}{9} and \frac{2}{3} to fractions with denominator 9.

$$\frac{25}{9}-\frac{6}{9}-\frac{2}{3}$$

Since \frac{25}{9} and \frac{6}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{25-6}{9}-\frac{2}{3}$$

Subtract 6 from 25 to get 19.

$$\frac{19}{9}-\frac{2}{3}$$

Least common multiple of 9 and 3 is 9. Convert \frac{19}{9} and \frac{2}{3} to fractions with denominator 9.

$$\frac{19}{9}-\frac{6}{9}$$

Since \frac{19}{9} and \frac{6}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{19-6}{9}$$

Subtract 6 from 19 to get 13.

$$\frac{13}{9}$$

Factor

$$\frac{13}{3 ^ {2}} = 1\frac{4}{9} = 1.4444444444444444$$