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\frac{1}{3}+x-\frac{3}{3}=0
Convert 1 to fraction \frac{3}{3}.
\frac{1-3}{3}+x=0
Since \frac{1}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.
-\frac{2}{3}+x=0
Subtract 3 from 1 to get -2.
x=\frac{2}{3}
Add \frac{2}{3} to both sides. Anything plus zero gives itself.