Solve 1/3+8/9-25/27=

$$\frac { 1 } { 3 } + \frac { 8 } { 9 } - \frac { 25 } { 27 } =$$

Evaluate

$$\frac{8}{27}\approx 0.296296296$$

Solution Steps

Least common multiple of 3 and 9 is 9. Convert \frac{1}{3} and \frac{8}{9} to fractions with denominator 9.

$$\frac{3}{9}+\frac{8}{9}-\frac{25}{27}$$

Since \frac{3}{9} and \frac{8}{9} have the same denominator, add them by adding their numerators.

$$\frac{3+8}{9}-\frac{25}{27}$$

Add 3 and 8 to get 11.

$$\frac{11}{9}-\frac{25}{27}$$

Least common multiple of 9 and 27 is 27. Convert \frac{11}{9} and \frac{25}{27} to fractions with denominator 27.

$$\frac{33}{27}-\frac{25}{27}$$

Since \frac{33}{27} and \frac{25}{27} have the same denominator, subtract them by subtracting their numerators.

$$\frac{33-25}{27}$$

Subtract 25 from 33 to get 8.

$$\frac{8}{27}$$

Factor

$$\frac{2 ^ {3}}{3 ^ {3}} = 0.2962962962962963$$