Solve 1/3+5/6div4/7

$$\frac { 1 } { 3 } + \frac { 5 } { 6 } \div \frac { 4 } { 7 }$$

Evaluate

$$\frac{43}{24}\approx 1.791666667$$

Solution Steps

Divide \frac{5}{6} by \frac{4}{7} by multiplying \frac{5}{6} by the reciprocal of \frac{4}{7}.

$$\frac{1}{3}+\frac{5}{6}\times \frac{7}{4}$$

Multiply \frac{5}{6} times \frac{7}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1}{3}+\frac{5\times 7}{6\times 4}$$

Do the multiplications in the fraction \frac{5\times 7}{6\times 4}.

$$\frac{1}{3}+\frac{35}{24}$$

Least common multiple of 3 and 24 is 24. Convert \frac{1}{3} and \frac{35}{24} to fractions with denominator 24.

$$\frac{8}{24}+\frac{35}{24}$$

Since \frac{8}{24} and \frac{35}{24} have the same denominator, add them by adding their numerators.

$$\frac{8+35}{24}$$

Add 8 and 35 to get 43.

$$\frac{43}{24}$$

Factor

$$\frac{43}{2 ^ {3} \cdot 3} = 1\frac{19}{24} = 1.7916666666666667$$