Solve 1/24.2+1/65.8

$$\frac { 1 } { 24.2 } + \frac { 1 } { 65.8 }$$

Evaluate

$$\frac{2250}{39809}\approx 0.056519882$$

Solution Steps

Expand \frac{1}{24.2} by multiplying both numerator and the denominator by 10.

$$\frac{10}{242}+\frac{1}{65.8}$$

Reduce the fraction \frac{10}{242} to lowest terms by extracting and canceling out 2.

$$\frac{5}{121}+\frac{1}{65.8}$$

Expand \frac{1}{65.8} by multiplying both numerator and the denominator by 10.

$$\frac{5}{121}+\frac{10}{658}$$

Reduce the fraction \frac{10}{658} to lowest terms by extracting and canceling out 2.

$$\frac{5}{121}+\frac{5}{329}$$

Least common multiple of 121 and 329 is 39809. Convert \frac{5}{121} and \frac{5}{329} to fractions with denominator 39809.

$$\frac{1645}{39809}+\frac{605}{39809}$$

Since \frac{1645}{39809} and \frac{605}{39809} have the same denominator, add them by adding their numerators.

$$\frac{1645+605}{39809}$$

Add 1645 and 605 to get 2250.

$$\frac{2250}{39809}$$

Factor

$$\frac{2 \cdot 3 ^ {2} \cdot 5 ^ {3}}{7 \cdot 47 \cdot 11 ^ {2}} = 0.05651988243864453$$