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\frac{1}{2}x-\frac{1}{4}-\frac{1}{6}x=\frac{1}{3}
Subtract \frac{1}{6}x from both sides.
\frac{1}{3}x-\frac{1}{4}=\frac{1}{3}
Combine \frac{1}{2}x and -\frac{1}{6}x to get \frac{1}{3}x.
\frac{1}{3}x=\frac{1}{3}+\frac{1}{4}
Add \frac{1}{4} to both sides.
\frac{1}{3}x=\frac{4}{12}+\frac{3}{12}
Least common multiple of 3 and 4 is 12. Convert \frac{1}{3} and \frac{1}{4} to fractions with denominator 12.
\frac{1}{3}x=\frac{4+3}{12}
Since \frac{4}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.
\frac{1}{3}x=\frac{7}{12}
Add 4 and 3 to get 7.
x=\frac{7}{12}\times 3
Multiply both sides by 3, the reciprocal of \frac{1}{3}.
x=\frac{7\times 3}{12}
Express \frac{7}{12}\times 3 as a single fraction.
x=\frac{21}{12}
Multiply 7 and 3 to get 21.
x=\frac{7}{4}
Reduce the fraction \frac{21}{12} to lowest terms by extracting and canceling out 3.