Solve for x
x\leq \frac{37}{2}
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\frac{1}{2}x\leq 37-\frac{3}{2}x
Add 8 and 29 to get 37.
\frac{1}{2}x+\frac{3}{2}x\leq 37
Add \frac{3}{2}x to both sides.
2x\leq 37
Combine \frac{1}{2}x and \frac{3}{2}x to get 2x.
x\leq \frac{37}{2}
Divide both sides by 2. Since 2 is positive, the inequality direction remains the same.
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