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\frac{x^{2}+18x+56}{2}
Factor out \frac{1}{2}.
a+b=18 ab=1\times 56=56
Consider x^{2}+18x+56. Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx+56. To find a and b, set up a system to be solved.
1,56 2,28 4,14 7,8
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 56.
1+56=57 2+28=30 4+14=18 7+8=15
Calculate the sum for each pair.
a=4 b=14
The solution is the pair that gives sum 18.
\left(x^{2}+4x\right)+\left(14x+56\right)
Rewrite x^{2}+18x+56 as \left(x^{2}+4x\right)+\left(14x+56\right).
x\left(x+4\right)+14\left(x+4\right)
Factor out x in the first and 14 in the second group.
\left(x+4\right)\left(x+14\right)
Factor out common term x+4 by using distributive property.
\frac{\left(x+4\right)\left(x+14\right)}{2}
Rewrite the complete factored expression.