Solve for x
x\in \mathrm{R}
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1x+10>3x-4+12-2x
Multiply both sides of the equation by 2. Since 2 is positive, the inequality direction remains the same.
1x+10>3x+8-2x
Add -4 and 12 to get 8.
1x+10>x+8
Combine 3x and -2x to get x.
1x+10-x>8
Subtract x from both sides.
10>8
Combine 1x and -x to get 0.
x\in \mathrm{R}
This is true for any x.
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Matrix
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Simultaneous equation
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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