Solve for x
x=1
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\frac{5}{2}x+\frac{3}{10}=\frac{1}{5}x+\frac{13}{5}
Combine \frac{1}{2}x and 2x to get \frac{5}{2}x.
\frac{5}{2}x+\frac{3}{10}-\frac{1}{5}x=\frac{13}{5}
Subtract \frac{1}{5}x from both sides.
\frac{23}{10}x+\frac{3}{10}=\frac{13}{5}
Combine \frac{5}{2}x and -\frac{1}{5}x to get \frac{23}{10}x.
\frac{23}{10}x=\frac{13}{5}-\frac{3}{10}
Subtract \frac{3}{10} from both sides.
\frac{23}{10}x=\frac{26}{10}-\frac{3}{10}
Least common multiple of 5 and 10 is 10. Convert \frac{13}{5} and \frac{3}{10} to fractions with denominator 10.
\frac{23}{10}x=\frac{26-3}{10}
Since \frac{26}{10} and \frac{3}{10} have the same denominator, subtract them by subtracting their numerators.
\frac{23}{10}x=\frac{23}{10}
Subtract 3 from 26 to get 23.
x=\frac{23}{10}\times \frac{10}{23}
Multiply both sides by \frac{10}{23}, the reciprocal of \frac{23}{10}.
x=1
Cancel out \frac{23}{10} and its reciprocal \frac{10}{23}.
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