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\frac{1}{2}x+\frac{2}{5}-\frac{1}{3}x=\frac{3}{4}
Subtract \frac{1}{3}x from both sides.
\frac{1}{6}x+\frac{2}{5}=\frac{3}{4}
Combine \frac{1}{2}x and -\frac{1}{3}x to get \frac{1}{6}x.
\frac{1}{6}x=\frac{3}{4}-\frac{2}{5}
Subtract \frac{2}{5} from both sides.
\frac{1}{6}x=\frac{15}{20}-\frac{8}{20}
Least common multiple of 4 and 5 is 20. Convert \frac{3}{4} and \frac{2}{5} to fractions with denominator 20.
\frac{1}{6}x=\frac{15-8}{20}
Since \frac{15}{20} and \frac{8}{20} have the same denominator, subtract them by subtracting their numerators.
\frac{1}{6}x=\frac{7}{20}
Subtract 8 from 15 to get 7.
x=\frac{7}{20}\times 6
Multiply both sides by 6, the reciprocal of \frac{1}{6}.
x=\frac{7\times 6}{20}
Express \frac{7}{20}\times 6 as a single fraction.
x=\frac{42}{20}
Multiply 7 and 6 to get 42.
x=\frac{21}{10}
Reduce the fraction \frac{42}{20} to lowest terms by extracting and canceling out 2.