Solve 1/2kg-quadg=125g

$$\frac { 1 } { 2 } k g - \quad g = 125 g$$

Solve for g

$$\left\{\begin{matrix}\\g=0\text{, }&\text{unconditionally}\\g\in \mathrm{R}\text{, }&k=252\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 125g from both sides.

$$\frac{1}{2}kg-g-125g=0$$

Combine -g and -125g to get -126g.

$$\frac{1}{2}kg-126g=0$$

Combine all terms containing g.

$$\left(\frac{1}{2}k-126\right)g=0$$

The equation is in standard form.

$$\left(\frac{k}{2}-126\right)g=0$$

Divide 0 by \frac{1}{2}k-126.

$$g=0$$

Solve for k

$$\left\{\begin{matrix}\\k=252\text{, }&\text{unconditionally}\\k\in \mathrm{R}\text{, }&g=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Add g to both sides.

$$\frac{1}{2}kg=125g+g$$

Combine 125g and g to get 126g.

$$\frac{1}{2}kg=126g$$

The equation is in standard form.

$$\frac{g}{2}k=126g$$

Divide both sides by \frac{1}{2}g.

$$\frac{2\times \frac{g}{2}k}{g}=\frac{2\times 126g}{g}$$

Dividing by \frac{1}{2}g undoes the multiplication by \frac{1}{2}g.

$$k=\frac{2\times 126g}{g}$$

Divide 126g by \frac{1}{2}g.

$$k=252$$