Solve 1/2ah=1/2(a+3)(h-3)

$$\frac { 1 } { 2 } a h = \frac { 1 } { 2 } ( a + 3 ) ( h - 3 )$$

Solve for a

$$a=h-3$$

Steps for Solving Linear Equation

Cancel out \frac{1}{2} on both sides.

$$ah=\left(a+3\right)\left(h-3\right)$$

Use the distributive property to multiply a+3 by h-3.

$$ah=ah-3a+3h-9$$

Subtract ah from both sides.

$$ah-ah=-3a+3h-9$$

Combine ah and -ah to get 0.

$$0=-3a+3h-9$$

Swap sides so that all variable terms are on the left hand side.

$$-3a+3h-9=0$$

Subtract 3h from both sides. Anything subtracted from zero gives its negation.

$$-3a-9=-3h$$

Add 9 to both sides.

$$-3a=-3h+9$$

The equation is in standard form.

$$-3a=9-3h$$

Divide both sides by -3.

$$\frac{-3a}{-3}=\frac{9-3h}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$a=\frac{9-3h}{-3}$$

Divide -3h+9 by -3.

$$a=h-3$$

Solve for h

$$h=a+3$$

Steps for Solving Linear Equation

Cancel out \frac{1}{2} on both sides.

$$ah=\left(a+3\right)\left(h-3\right)$$

Use the distributive property to multiply a+3 by h-3.

$$ah=ah-3a+3h-9$$

Subtract ah from both sides.

$$ah-ah=-3a+3h-9$$

Combine ah and -ah to get 0.

$$0=-3a+3h-9$$

Swap sides so that all variable terms are on the left hand side.

$$-3a+3h-9=0$$

Add 3a to both sides. Anything plus zero gives itself.

$$3h-9=3a$$

Add 9 to both sides.

$$3h=3a+9$$

Divide both sides by 3.

$$\frac{3h}{3}=\frac{3a+9}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$h=\frac{3a+9}{3}$$

Divide 9+3a by 3.

$$h=a+3$$