Solve for m
m=\frac{3}{2\left(3x+\pi \right)}
x\neq -\frac{\pi }{3}
Solve for x
x=-\frac{\pi }{3}+\frac{1}{2m}
m\neq 0
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3-6xm=2\pi m
Multiply both sides of the equation by 6, the least common multiple of 2,3.
3-6xm-2\pi m=0
Subtract 2\pi m from both sides.
-6xm-2\pi m=-3
Subtract 3 from both sides. Anything subtracted from zero gives its negation.
\left(-6x-2\pi \right)m=-3
Combine all terms containing m.
\frac{\left(-6x-2\pi \right)m}{-6x-2\pi }=-\frac{3}{-6x-2\pi }
Divide both sides by -6x-2\pi .
m=-\frac{3}{-6x-2\pi }
Dividing by -6x-2\pi undoes the multiplication by -6x-2\pi .
m=\frac{3}{2\left(3x+\pi \right)}
Divide -3 by -6x-2\pi .
3-6xm=2\pi m
Multiply both sides of the equation by 6, the least common multiple of 2,3.
-6xm=2\pi m-3
Subtract 3 from both sides.
\left(-6m\right)x=2\pi m-3
The equation is in standard form.
\frac{\left(-6m\right)x}{-6m}=\frac{2\pi m-3}{-6m}
Divide both sides by -6m.
x=\frac{2\pi m-3}{-6m}
Dividing by -6m undoes the multiplication by -6m.
x=-\frac{\pi }{3}+\frac{1}{2m}
Divide 2\pi m-3 by -6m.
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