Solve 1/2(-3)^2+3q-2=1

$$\frac { 1 } { 2 } ( - 3 ) ^ { 2 } + 3 q - 2 = 1$$

Solve for q

$$q=-\frac{1}{2}=-0.5$$

Steps for Solving Linear Equation

Calculate -3 to the power of 2 and get 9.

$$\frac{1}{2}\times 9+3q-2=1$$

Multiply \frac{1}{2} and 9 to get \frac{9}{2}.

$$\frac{9}{2}+3q-2=1$$

Convert 2 to fraction \frac{4}{2}.

$$\frac{9}{2}+3q-\frac{4}{2}=1$$

Since \frac{9}{2} and \frac{4}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-4}{2}+3q=1$$

Subtract 4 from 9 to get 5.

$$\frac{5}{2}+3q=1$$

Subtract \frac{5}{2} from both sides.

$$3q=1-\frac{5}{2}$$

Convert 1 to fraction \frac{2}{2}.

$$3q=\frac{2}{2}-\frac{5}{2}$$

Since \frac{2}{2} and \frac{5}{2} have the same denominator, subtract them by subtracting their numerators.

$$3q=\frac{2-5}{2}$$

Subtract 5 from 2 to get -3.

$$3q=-\frac{3}{2}$$

Divide both sides by 3.

$$q=\frac{-\frac{3}{2}}{3}$$

Express \frac{-\frac{3}{2}}{3} as a single fraction.

$$q=\frac{-3}{2\times 3}$$

Multiply 2 and 3 to get 6.

$$q=\frac{-3}{6}$$

Reduce the fraction \frac{-3}{6} to lowest terms by extracting and canceling out 3.

$$q=-\frac{1}{2}$$