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\frac{1}{2}\times 80=25+64-x^{2}
Multiply both sides by 80.
40=25+64-x^{2}
Multiply \frac{1}{2} and 80 to get 40.
40=89-x^{2}
Add 25 and 64 to get 89.
89-x^{2}=40
Swap sides so that all variable terms are on the left hand side.
-x^{2}=40-89
Subtract 89 from both sides.
-x^{2}=-49
Subtract 89 from 40 to get -49.
x^{2}=\frac{-49}{-1}
Divide both sides by -1.
x^{2}=49
Fraction \frac{-49}{-1} can be simplified to 49 by removing the negative sign from both the numerator and the denominator.
x=7 x=-7
Take the square root of both sides of the equation.
\frac{1}{2}\times 80=25+64-x^{2}
Multiply both sides by 80.
40=25+64-x^{2}
Multiply \frac{1}{2} and 80 to get 40.
40=89-x^{2}
Add 25 and 64 to get 89.
89-x^{2}=40
Swap sides so that all variable terms are on the left hand side.
89-x^{2}-40=0
Subtract 40 from both sides.
49-x^{2}=0
Subtract 40 from 89 to get 49.
-x^{2}+49=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\left(-1\right)\times 49}}{2\left(-1\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 0 for b, and 49 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-1\right)\times 49}}{2\left(-1\right)}
Square 0.
x=\frac{0±\sqrt{4\times 49}}{2\left(-1\right)}
Multiply -4 times -1.
x=\frac{0±\sqrt{196}}{2\left(-1\right)}
Multiply 4 times 49.
x=\frac{0±14}{2\left(-1\right)}
Take the square root of 196.
x=\frac{0±14}{-2}
Multiply 2 times -1.
x=-7
Now solve the equation x=\frac{0±14}{-2} when ± is plus. Divide 14 by -2.
x=7
Now solve the equation x=\frac{0±14}{-2} when ± is minus. Divide -14 by -2.
x=-7 x=7
The equation is now solved.