Solve 1/2+x=y/8-x

$$\frac { 1 } { 2 } + x = \frac { y } { 8 } - x$$

Solve for x

$$x=\frac{y-4}{16}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 8, the least common multiple of 2,8.

$$4+8x=y-8x$$

Add 8x to both sides.

$$4+8x+8x=y$$

Combine 8x and 8x to get 16x.

$$4+16x=y$$

Subtract 4 from both sides.

$$16x=y-4$$

Divide both sides by 16.

$$\frac{16x}{16}=\frac{y-4}{16}$$

Dividing by 16 undoes the multiplication by 16.

$$x=\frac{y-4}{16}$$

Divide y-4 by 16.

$$x=\frac{y}{16}-\frac{1}{4}$$

Solve for y

$$y=16x+4$$

Solution Steps

Multiply both sides of the equation by 8, the least common multiple of 2,8.

$$4+8x=y-8x$$

Swap sides so that all variable terms are on the left hand side.

$$y-8x=4+8x$$

Add 8x to both sides.

$$y=4+8x+8x$$

Combine 8x and 8x to get 16x.

$$y=4+16x$$