Solve 1/12x-1/12=1/8x+1/6-frac{1}{6}x

$$\frac { 1 } { 12 } x - \frac { 1 } { 12 } = \frac { 1 } { 8 } x + \frac { 1 } { 6 } - \frac { 1 } { 6 } x$$

Solve for x

$$x=2$$

Steps for Solving Linear Equation

Combine \frac{1}{8}x and -\frac{1}{6}x to get -\frac{1}{24}x.

$$\frac{1}{12}x-\frac{1}{12}=-\frac{1}{24}x+\frac{1}{6}$$

Add \frac{1}{24}x to both sides.

$$\frac{1}{12}x-\frac{1}{12}+\frac{1}{24}x=\frac{1}{6}$$

Combine \frac{1}{12}x and \frac{1}{24}x to get \frac{1}{8}x.

$$\frac{1}{8}x-\frac{1}{12}=\frac{1}{6}$$

Add \frac{1}{12} to both sides.

$$\frac{1}{8}x=\frac{1}{6}+\frac{1}{12}$$

Least common multiple of 6 and 12 is 12. Convert \frac{1}{6} and \frac{1}{12} to fractions with denominator 12.

$$\frac{1}{8}x=\frac{2}{12}+\frac{1}{12}$$

Since \frac{2}{12} and \frac{1}{12} have the same denominator, add them by adding their numerators.

$$\frac{1}{8}x=\frac{2+1}{12}$$

Add 2 and 1 to get 3.

$$\frac{1}{8}x=\frac{3}{12}$$

Reduce the fraction \frac{3}{12} to lowest terms by extracting and canceling out 3.

$$\frac{1}{8}x=\frac{1}{4}$$

Multiply both sides by 8, the reciprocal of \frac{1}{8}.

$$x=\frac{1}{4}\times 8$$

Multiply \frac{1}{4} and 8 to get \frac{8}{4}.

$$x=\frac{8}{4}$$

Divide 8 by 4 to get 2.

$$x=2$$