Evaluate
\frac{\sqrt{7}+2}{3}\approx 1.54858377
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\frac{\sqrt{7}+2}{\left(\sqrt{7}-2\right)\left(\sqrt{7}+2\right)}
Rationalize the denominator of \frac{1}{\sqrt{7}-2} by multiplying numerator and denominator by \sqrt{7}+2.
\frac{\sqrt{7}+2}{\left(\sqrt{7}\right)^{2}-2^{2}}
Consider \left(\sqrt{7}-2\right)\left(\sqrt{7}+2\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\sqrt{7}+2}{7-4}
Square \sqrt{7}. Square 2.
\frac{\sqrt{7}+2}{3}
Subtract 4 from 7 to get 3.
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