Solve 1+x/I-x=h

$$\frac { 1 + x } { I - x } = h$$

Solve for h

$$h=-\frac{x+1}{x-I}$$

$$x\neq I$$

Steps for Solving Linear Equation

Multiply both sides of the equation by -x+I.

$$1+x=h\left(-x+I\right)$$

Use the distributive property to multiply h by -x+I.

$$1+x=-hx+hI$$

Swap sides so that all variable terms are on the left hand side.

$$-hx+hI=1+x$$

Combine all terms containing h.

$$\left(-x+I\right)h=1+x$$

The equation is in standard form.

$$\left(I-x\right)h=x+1$$

Divide both sides by I-x.

$$\frac{\left(I-x\right)h}{I-x}=\frac{x+1}{I-x}$$

Dividing by I-x undoes the multiplication by I-x.

$$h=\frac{x+1}{I-x}$$

Solve for I

$$\left\{\begin{matrix}I=\frac{hx+x+1}{h}\text{, }&x\neq -1\text{ and }h\neq 0\\I\neq -1\text{, }&h=0\text{ and }x=-1\end{matrix}\right.$$