Skip to main content
Solve for x
Tick mark Image
Graph

Similar Problems from Web Search

Share

1-x>0 1-x<0
Denominator 1-x cannot be zero since division by zero is not defined. There are two cases.
-x>-1
Consider the case when 1-x is positive. Move 1 to the right hand side.
x<1
Divide both sides by -1. Since -1 is negative, the inequality direction is changed.
1+x>1-x
The initial inequality does not change the direction when multiplied by 1-x for 1-x>0.
x+x>-1+1
Move the terms containing x to the left hand side and all other terms to the right hand side.
2x>0
Combine like terms.
x>0
Divide both sides by 2. Since 2 is positive, the inequality direction remains the same.
x\in \left(0,1\right)
Consider condition x<1 specified above.
-x<-1
Now consider the case when 1-x is negative. Move 1 to the right hand side.
x>1
Divide both sides by -1. Since -1 is negative, the inequality direction is changed.
1+x<1-x
The initial inequality changes the direction when multiplied by 1-x for 1-x<0.
x+x<-1+1
Move the terms containing x to the left hand side and all other terms to the right hand side.
2x<0
Combine like terms.
x<0
Divide both sides by 2. Since 2 is positive, the inequality direction remains the same.
x\in \emptyset
Consider condition x>1 specified above.
x\in \left(0,1\right)
The final solution is the union of the obtained solutions.